2x^2+4x=336

Solution for 2x^2+4x=336 equation:

2x^2+4x=336

We move all terms to the left:

2x^2+4x-(336)=0

a = 2; b = 4; c = -336;
Δ = b2-4ac
Δ = 42-4·2·(-336)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-52}{2*2}=\frac{-56}{4}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+52}{2*2}=\frac{48}{4}
=12
$